Angel Ivanov Raychev

Rectangle capture time: exact coverage

Rectangle overview · Exact coverage · Remaining gaps · Progress against the goal · Manuscript · Parked extensions

This page is generated from the private project’s canonical assessment. Named research files and certificates are preserved in the mathematical sources package; theorem links lead to the current manuscript-derived proofs. Download this assessment.

Updated 29 October 2026. Write w≤nw\le n for the positive side lengths and kk for the constant daily budget; put V=wnV=wn. The princess starts anywhere, inspections are simultaneous, and she must move across one edge after each unsuccessful day. The immediate goal is matching constructive upper and rigorous lower bounds everywhere; the eventual fixed-size numerical goal and direct optimal inspections are unchanged.

Current uniform bounds

For every feasible input k≥⌊w/2⌋+1k\ge\lfloor w/2\rfloor+1,

Lk(w,n)≤Tk(w,n)≤Uk(w,n),Uk(w,n)−Lk(w,n)≤2.L_k(w,n)\le T_k(w,n)\le U_k(w,n),\qquad U_k(w,n)-L_k(w,n)\le2.

No width, length or feasible budget is omitted. Take the maximum of all accepted lower bounds and the minimum of all physical upper bounds, retaining every stronger earlier result. Odd-by-odd rectangles retain exact joint evaluation at every budget; even-area rectangles now have a universal two-day ceiling, with exact and one-day subranges below. This improves the previous public four-day ceiling and the preceding private three-day ceiling. It does not assert a two-day improvement on every instance.

For odd w=2b+1w=2b+1 with b≥2b\ge2, even nn, and b+1≤k<Z=wn/2−b2b+1\le k<Z=wn/2-b^2, put p=P(k)p=P(k) and q=P(⌊k/2⌋)q=P(\lfloor k/2\rfloor), where P(c)P(c) is the compatible physical-prefix gate recurrence. The new comparison, for 0≤c≤k0\le c\le k, gives

max⁡(2p−1,2q−2)≤Tk(w,n)≤min⁡(2p+2,2q+1),q∈{p,p+1}.\max(2p-1,2q-2)\le T_k(w,n)\le\min(2p+2,2q+1),\qquad q\in\{p,p+1\}.

Widths one and three and the range k≥Zk\ge Z use the retained exact formulas; the odd-width argument above does not silently extend its guards. The earlier even-width two-day results cover all even widths. High-budget and narrow-board formulas remain stronger wherever applicable. The lower bound concerns arbitrary inspection histories; the upper bound has actual inspection words.

New exact range: every budget at odd widths at least 8,193

Let w=2b+1w=2b+1, b≥4096b\ge4096, and let n≥wn\ge w be any even length. Put h=wn/2h=wn/2 and B=b(b+1)B=b(b+1).

  • k≤bk\le b: capture is impossible.
  • b+1≤k≤Bb+1\le k\le B: Tk(w,n)=P(k)+P(⌊k/2⌋)+1T_k(w,n)=P(k)+P(\lfloor k/2\rfloor)+1, with attaining prefix/palindrome inspections.
  • B+1≤k<hB+1\le k<h: the retained high-budget formula gives the exact value and inspections.
  • h≤k<2hh\le k<2h: two days; k≥2hk\ge2h: one day.

This covers every budget and every length with the stated parity and width. The low- and middle-budget value remains a recurrence, not an O(1)-operation expression. A further exact range, not subsumed at smaller widths, is b≥512b\ge512 and 3b≤k≤⌊15b/4⌋3b\le k\le\lfloor15b/4\rfloor at every even length.

New physical constructions and tools

Matching lower bounds and independently replayed whole-board strategies establish T48(64,93)=285T_{48}(64,93)=285 and T72(102,124)=413T_{72}(102,124)=413. The old fixed-corner construction takes 286 and 414 respectively. Thus its universal optimality is false. These examples identify a necessary change in the general construction, rather than replace the all-parameter objective.

A conditional paired-boundary theorem now constructs a middle passage from actual reached head and suffix states, preserving phase and inherited overlap. It does not assert that every favorable raw boundary shape can arrive at its scalar clock. A 12-by-12, budget-7 target disproves that stronger claim: its scalar estimate is eight updates, while the specified target first arrives at ten. This is a partial-state arrival statement, not the board’s capture time.

The 25 October literal cutset and endpoint-intersection evaluators are retained. They reconstruct physical strategies and reduce the state exponent in their stated parameter ranges, but can degenerate to generic finite-state search. Exact finite computability is not the final numerical classification.

Evidence and formalization

The current checkpoint and proofs identify the ordinary proofs and internal independent reviews. The 29 October source supplement includes all dependencies and precise guards. These are not external peer reviews. The formerly unverified 751-profile comparison was independently verified in the later 24 October continuation; its old candidate archive preserves historical status only.

The new Lean module PairedCompression.lean checks an abstract complement-dual compression and paired-overlap theorem with explicit hypotheses. The global two-day bound, all-budget 8,193-width theorem and new physical constructions are not complete Lean classifications. Paths and two rows retain complete physical-game proofs. See formal coverage.

Retained numerical families and exact evaluators

The detailed earlier ranges below remain valid. Any weaker upper/lower ceilings are superseded by the current two-day bound above; none of their stronger conclusions is discarded. “Numerically complete” means a delivered fixed-size expression with an absolute bounded number of standard numerical operations. An exact recurrence or optimizer does not meet that final requirement.

1. Feasibility is already a bounded numerical answer

For every rectangle,

Tk(w,n)<∞⟺k≥⌊w/2⌋+1.T_k(w,n)<\infty\quad\Longleftrightarrow\quad k\ge\lfloor w/2\rfloor+1.

This is the rectangular-grid feasibility theorem from the existing literature, with the path and single-room conventions treated separately in our sources. Its credit remains distinct from the later capture-time results. The general rectangle feasibility theorem is not a completed physical-game Lean theorem in this project. Paths and two-row rectangles have that complete formal bridge.

If k≥Vk\ge V, the answer is one day: inspect every room. If V≥2V\ge2 and ⌊V/2⌋≤k<V\lfloor V/2\rfloor\le k<V, the answer is two days. A bipartition-class inspection captures one initial cohort and its same-color repetition captures the other; no single day can inspect the whole board. These endpoint clauses are already proved in the path, narrow-grid, and general rectangle sources.

Sources: sec:foundations, the introduction’s cited feasibility result, thm:bounded-odd-frontier, thm:even-rectangle-high-budget, and thm:odd-short-even-high-budget. No new feasibility or endpoint theorem is being asserted by this assessment.

2. The delivered bounded-formula union

The following union describes the accepted formula families, not every isolated numerical instance present in the experimental receipts. It is a fixed finite union. All comparisons, remainders, and indicators in the formulas are standard arithmetic with fixed finite case distinctions.

Paths: w=1, every n and k

For k≥nk\ge n, Tk(1,n)=1T_k(1,n)=1. For one inspection, the remaining cases are T1(1,2)=2T_1(1,2)=2 and T1(1,n)=2n−4T_1(1,n)=2n-4 for n≥3n\ge3. For n>k≥2n>k\ge2,

Tk(1,n)=⌈2n−42k−1⌉+ε,T_k(1,n)=\left\lceil\frac{2n-4}{2k-1}\right\rceil+\varepsilon,

where ε=1\varepsilon=1 exactly when n≡k+1(mod2k−1)n\equiv k+1\pmod{2k-1} and n,kn,k are not both even.

Value and construction: matching unrestricted lower and upper bounds; direct room-indexed sweeps. Verification: ordinary proofs, independent checks, and complete physical-game Lean classification in PathClassification.lean. Source: eq:path-main, sec:paths.

Two rows: w=2, every n>=2 and k

Budget one is impossible; budgets at least 2n2n take one day. Otherwise put A=n−1A=n-1, D=k−1D=k-1. Then

Tk(2,n)=⌈2AD⌉+1{D even and A≡D/2(modD)}.T_k(2,n)=\left\lceil\frac{2A}{D}\right\rceil+ \mathbf1_{\{D\text{ even and }A\equiv D/2\pmod D\}}.

Value and construction: exact two-counter lower bound with directly specified interval sweeps and at most one shared day. Verification: complete physical-game Lean theorem in LadderGame.lean, in addition to the ordinary proof and semantic review. Sources: eq:ladder-main, sec:two-rows.

Three rows: w=3, every n>=3 and k

Use the feasibility and one-/two-day clauses first. In the remaining range 2≤k<⌊3n/2⌋2\le k<\lfloor3n/2\rfloor, write 3n−4=q(2k−3)+r3n-4=q(2k-3)+r, with 0≤r<2k−30\le r<2k-3. The answer is

{2q,r=0,2q+1,r>0 and k≥r+4−1{n even,q odd},2q+2,otherwise.\begin{cases} 2q,&r=0,\\ 2q+1,&r>0\text{ and }k\ge r+4-\mathbf1_{\{n\text{ even},q\text{ odd}\}},\\ 2q+2,&\text{otherwise}. \end{cases}

Value and construction: matching bounds and attaining oriented prefix or envelope sweeps. Verification: reviewed ordinary proof; no complete physical-game Lean classification. Sources: eq:three-main, sec:three-rows.

Four rows: w=4, every n>=4 and k

Use the endpoint clauses first. For 3≤k<2n3\le k<2n, write 2n−2=q(k−2)+r2n-2=q(k-2)+r, 0≤r<k−20\le r<k-2. The answer is

{2q,r=0,2q+1,r=1 or (r≥2 and k≥2r+4),2q+2,otherwise.\begin{cases} 2q,&r=0,\\ 2q+1,&r=1\text{ or }(r\ge2\text{ and }k\ge2r+4),\\ 2q+2,&\text{otherwise}. \end{cases}

Value and construction: matching unrestricted bounds and backward envelope construction. This range is now a specialization of the sharper all-even-width theorem rather than an additional obligation. Verification: ordinary proof, with reusable Lean components but no full physical classification. Sources: eq:four-main, sec:four-rows, thm:even-rectangle-high-budget.

Five rows: w=5, every n>=5 and k

Budgets at most two are impossible. At budget three, for both length parities, T3(5,n)=10n−20T_3(5,n)=10n-20. At budget four,

T4(5,n)={2⌈(5n−8)/3⌉,n even,2⌈(5n−9)/3⌉+21{3∣n},n odd.T_4(5,n)= \begin{cases} 2\lceil(5n-8)/3\rceil,&n\text{ even},\\ 2\lceil(5n-9)/3\rceil+2\mathbf1_{\{3\mid n\}},&n\text{ odd}. \end{cases}

For 5≤k<⌊5n/2⌋5\le k<\lfloor5n/2\rfloor, write 5n−6=q(2k−5)+r5n-6=q(2k-5)+r, 0≤r<2k−50\le r<2k-5. Set

J(0)=0, J(1)=2, J(2)=3, J(3)=J(4)=4,J(r)=⌈(r+5)/2⌉(r≥5),J(0)=0,\ J(1)=2,\ J(2)=3,\ J(3)=J(4)=4, \qquad J(r)=\lceil(r+5)/2\rceil\quad(r\ge5),

and δ(r)=1{r∈{1,2,4} or (r≥5 odd)}\delta(r)=\mathbf1_{\{r\in\{1,2,4\}\ \text{or}\ (r\ge5\text{ odd})\}}. For r=0r=0 the answer is 2q2q. For r>0r>0 it is 2q+12q+1 exactly when

2J(r)+1{n odd}δ(r)≤k;2J(r)+\mathbf1_{\{n\text{ odd}\}}\delta(r)\le k;

otherwise it is 2q+22q+2. Larger budgets use the one-/two-day clauses.

Value and construction: all lengths and budgets have matching bounds and attaining specified sweeps. Verification: reviewed ordinary proofs, unbounded symbolic reductions, independent finite certificates, and selected Lean arithmetic inequalities. The geometric-to-game interpretation and full five-row classification remain outside the complete Lean coverage. Sources: thm:five-row-time, thm:five-even-all-budgets, thm:five-odd-all-budgets.

Every even width above its quadratic budget

Let w=2r≥2w=2r\ge2, n≥wn\ge w, h=rnh=rn, and k≥max⁡{r+1,r(r−1)+1}k\ge\max\{r+1,r(r-1)+1\}. If k<hk<h, write

h−r=q(k−r)+s,0≤s<k−r,J(s)=s+min⁡{⌈s⌉,r}(s>0).h-r=q(k-r)+s,\qquad0\le s<k-r, \quad J(s)=s+\min\{\lceil\sqrt s\rceil,r\}\quad(s>0).

The answer is 2q2q when s=0s=0; otherwise it is 2q+12q+1 if 2J(s)≤k2J(s)\le k, and 2q+22q+2 if not. Higher budgets have the endpoint values. Both parities of nn are included, with no length threshold other than n≥wn\ge w.

Value and construction: exact unrestricted lower bounds and a prescribed backward enlargement/erosion construction; there is no strategy optimization in this construction. The text allows the choice of a minimal missing ideal element, so a common deterministic room order remains an exposition detail, not a new mathematical existence issue. Verification: ordinary geometric proofs and independent reviews; ClippedPyramidErosion.lean verifies the physical erosion component, not the complete construction or classification. Source: thm:even-rectangle-high-budget.

Every odd width and odd length above its quadratic budget

Let w=2r+1≥3w=2r+1\ge3, n≥wn\ge w odd, h=(wn−1)/2h=(wn-1)/2, and k≥r2+1k\ge r^2+1. For k<hk<h, write

wn−w−1=q(2k−w)+s,0≤s<2k−w.wn-w-1=q(2k-w)+s,\qquad0\le s<2k-w.

The following operations are explicitly standard roots, not hidden searches:

R(x)=⌈x⌉,Q(x)=⌈1+1+4x2⌉.R(x)=\lceil\sqrt x\rceil,\qquad Q(x)=\left\lceil\frac{1+\sqrt{1+4x}}2\right\rceil.

For positive xx, put L0(x)=x+min⁡{R(x),r}L_0(x)=x+\min\{R(x),r\}, L1(x)=x+min⁡{Q(x),r+1}L_1(x)=x+\min\{Q(x),r+1\}, and L0(0)=L1(0)=0L_0(0)=L_1(0)=0. For positive ss, define

J(s)={L1(s/2),s even,L0((s+1)/2),s odd,δ(s)={L0(s/2+1)−L1(s/2),s even,L1((s+1)/2)−L0((s+1)/2),s odd.J(s)=\begin{cases}L_1(s/2),&s\text{ even},\\ L_0((s+1)/2),&s\text{ odd},\end{cases}\qquad \delta(s)=\begin{cases}L_0(s/2+1)-L_1(s/2),&s\text{ even},\\ L_1((s+1)/2)-L_0((s+1)/2),&s\text{ odd}.\end{cases}

The answer is 2q2q for s=0s=0; for s>0s>0, it is 2q+12q+1 if 2J(s)+δ(s)≤k2J(s)+\delta(s)\le k, and 2q+22q+2 otherwise. Higher budgets use the endpoint values. The root-free specialization at k≥2r2+1k\ge2r^2+1 is useful but does not enlarge numerical completion: roots are already permitted.

Value and construction: matching bounds and directly specified prefix sweeps, with at most one shared day. Verification: ordinary proof and independent reviews; full physical Lean classification is incomplete. Sources: thm:odd-rectangle-high-budget, cor:odd-rectangle-root-free-time.

Every odd width and even length above its quadratic budget

Let w=2r+1≥3w=2r+1\ge3, n≥wn\ge w even, and k≥r(r+1)+1k\ge r(r+1)+1. Use exactly the preceding quotient, remainder, and JJ, but omit the δ\delta correction. Thus the positive-remainder middle case is 2J(s)≤k2J(s)\le k. Endpoint values apply at k≥wn/2k\ge wn/2.

Value and construction: matching arbitrary-strategy lower bounds and backward envelope inspections with optional central overlap. The construction is prescribed, with the same harmless ideal-element tie-choice as the even-width proof. Verification: ordinary proofs and selected formal tools; not a complete physical Lean theorem. Source: thm:odd-short-even-high-budget.

Fixed minimum-budget odd widths through fifteen

For odd n≥wn\ge w, the fixed list

(w,Cw)=(3,8),(5,20),(7,44),(9,84),(11,136),(13,208),(15,288)(w,C_w)=(3,8),(5,20),(7,44),(9,84),(11,136),(13,208),(15,288)

gives T(w+1)/2(w,n)=2wn−CwT_{(w+1)/2}(w,n)=2wn-C_w. This fixed finite list of constants qualifies as a bounded numerical expression. It must not be discarded merely because the wider theorem supersedes its mathematical conclusion: that wider theorem has not yet evaluated its width-dependent constant in bounded form. Widths three and five overlap the complete narrow families above.

Value and construction: matching bounds and greedy compatible-prefix attainment. Verification: ordinary unbounded proofs with exact finite rational certificates and independent reviews, but not a complete Lean classification. Source: the constant list in thm:odd-minimum-budget and research/odd-minimum-budget-all-lengths.md.

Seven rows and five inspections

For every odd n≥7n\ge7,

T5(7,n)=2⌈7n−163⌉.T_5(7,n)=2\left\lceil\frac{7n-16}{3}\right\rceil.

Value and construction: matching bounds, finitely supplied base schedules, and explicit plateau insertion; greedy prefix sweeps need no search over strategies. Verification: ordinary proof plus independently replayed rational certificates. There is no complete physical Lean theorem. Source: thm:seven-row-five-probe-time.

Seven rows, every odd length and every budget

The remaining budgets six through nine now have bounded expressions. For n≥7n\ge7 odd, k∈{6,8,9}k\in\{6,8,9\}, put D=2k−7D=2k-7, q=⌊(n−7)/(2D)⌋q=\lfloor(n-7)/(2D)\rfloor, and j=(n−7)/2−Dqj=(n-7)/2-Dq. Then

Tk(7,n)=28q+ck(j).T_k(7,n)=28q+c_k(j).

The fixed lists, starting at index zero, are

  • c6=(16,21,26,32,38)c_6=(16,21,26,32,38).
  • c8=(10,12,16,18,22,25,28,31,34)c_8=(10,12,16,18,22,25,28,31,34).
  • c9=(8,10,13,16,18,20,23,26,28,30,33)c_9=(8,10,13,16,18,20,23,26,28,30,33).

The fourth formula is T7(7,n)=2n−2T_7(7,n)=2n-2. Combined with the already proved minimum-budget, five-inspection and high-budget results, this covers all budgets on every seven-row odd-length rectangle. Even lengths remain in their separately stated range; this is not an all-seven-row classification.

Value and construction: exact values, fixed numerical expressions and prescribed prefix/palindrome inspections. Proof: the 296 short cases exhaust the complement of the explicit unbounded scalar-onset theorem. An independent full Pareto calculation checks every quota split and agrees with the earlier retained solver; an ordinary period proof covers unbounded lengths. There is no new complete physical Lean theorem. Source: thm:bridge-seven-odd, research/bridge-odd-clock-width-seven-check.json.

The complete first budget below the former even-width threshold

For w=2rw=2r, r≥3r\ge3, n≥2rn\ge2r, and k=r(r−1)k=r(r-1), put

h=rn,s=r(r−2),j=max⁡{0,⌊(h−k−s−3)/s⌋},z=h−(j+1)s−k−1,c=z+⌈z⌉.h=rn,\quad s=r(r-2),\quad j=\max\{0,\lfloor(h-k-s-3)/s\rfloor\},\quad z=h-(j+1)s-k-1,\quad c=z+\lceil\sqrt z\rceil.

Then

Tk(2r,n)=2(j+3)−1{2c≤k}.T_k(2r,n)=2(j+3)-\mathbf1_{\{2c\le k\}}.

This is a fixed-size expression on the entire stated family. Its direct optimal construction includes an explicit shape change for width16, budget56, and n=22 modulo12. That class has no remaining exception. Proof and construction: research/bridge-boundary-numeric-quadratic-edge.md and research/bridge-quadratic-edge-exception.md.

Twenty-five rows at the minimum budget, every even length

For every even n≥26n\ge26,

T13(25,n)=50n−925.T_{13}(25,n)=50n-925.

The proof combines a uniform joint time28 obstruction, persistent radius geometry and merger, a finite terminal certificate, and a prescribed physical construction. It covers all even lengths, not only the checked smallest board. Source: research/bridge-boundary-numeric-25-exact.md.

Fixed-operation evaluations that supply further exact subfamilies

On odd rectangles w=2r+1w=2r+1, whenever

16(2k−w)≥r2,16(2k-w)\ge r^2,

each solo clock or prescribed-day residual uses at most49 conditional paired-map blocks and one bulk division. These are fixed compositions of the displayed square/pronic-root maps. Four evaluations give the solo time and central residual test. No block count depends on the parameters.

This gives an exact bounded expression and direct optimal inspections where the scalar test is proved necessary: the low-linear or cubic range, the explicit improved onset, the fixed recent-reset condition below, or an already classified family. On other inputs it evaluates the solo bracket and sufficient central test only. Source: thm:bridge-quadratic-solo.

On even widths w=2r≥4w=2r\ge4, if

k≥r+2,k<rn,16(k−r−1)≥r2,k\ge r+2,\quad k<rn,\quad16(k-r-1)\ge r^2,

the critical-corner lower bound LL and a physical upper bound UU use at most168 elementary blocks and four divisions together. Whenever L=UL=U, their common value is an exact fixed-size answer, with the prescribed upper construction optimal. The comparison itself has bounded size. When L<UL<U, this theorem supplies numerical bounds only. The block definitions are in research/bridge-boundary-numeric-budget.md; fixing16 once is essential to the assertion.

3. Residual domain under the eventual fixed-size numerical criterion

The original scope baseline had four residual families. The bounded-formula union, including the September improvements above, leaves the following containing ranges. October exact recurrences close value gaps inside these ranges but do not remove them from the fixed-size numerical obligations. These are formula-family obligations; isolated certified values inside them retain their own exact status.

  1. Even short side: w=2r≥6w=2r\ge6, n≥wn\ge w, r+1≤k≤r(r−1)−1r+1\le k\le r(r-1)-1, excluding inputs where the preceding fixed168-block evaluation is defined and returns L=UL=U.
  2. Odd short side and even long side: w=2r+1≥7w=2r+1\ge7, n≥wn\ge w even, r+1≤k≤r(r+1)r+1\le k\le r(r+1), excluding (w,k)=(25,13)(w,k)=(25,13).
  3. Odd-by-odd minimum budget beyond the supplied constants: w=2r+1≥17w=2r+1\ge17, n≥wn\ge w odd, k=r+1k=r+1.
  4. Odd-by-odd intermediate budgets: w=2r+1≥9w=2r+1\ge9, n≥wn\ge w odd, r+2≤k≤r2r+2\le k\le r^2, excluding inputs where 16(2k−w)≥r216(2k-w)\ge r^2 and one of the accepted scalar-decision conditions in Section4 holds.

These are evaluation obligations, not claims of unknown exact values at every input. None of these four infinite families has disappeared altogether. Width6 now leaves budgets4 and5; odd-length width7 has no remaining budget; even-length width7 still has general obligations. Minimum-budget odd widths beyond15 retain their original width-clock evaluation gap. See BOX_RECONCILIATION.md for the before/after assessment against the exact scope-baseline commit.

4. Exactness and direct strategies on odd rectangles

Let w=2r+1w=2r+1, n≥wn\ge w odd, E=(wn+1)/2E=(wn+1)/2, M=E−1M=E-1. For r+1≤k<Mr+1\le k<M, define the simultaneous solo deficit recurrence

D0(0)=D1(0)=0,D0(t+1)=I0(D1(t)+k),D1(t+1)=I1(D0(t)+k).D_0(0)=D_1(0)=0,\qquad D_0(t+1)=I_0(D_1(t)+k),\quad D_1(t+1)=I_1(D_0(t)+k).

Here R(z)=⌈z⌉R(z)=\lceil\sqrt z\rceil, ρ(z)=⌈(1+4z−1)/2⌉\rho(z)=\lceil(\sqrt{1+4z}-1)/2\rceil, and the proper inverses are

I0(z)=z−min⁡{ρ(z),r,ρ(M−z)}(0≤z<M),I_0(z)=z-\min\{\rho(z),r,\rho(M-z)\}\quad(0\le z<M), I1(z)=z−min⁡{R(z),r+1,1+R(E−z)}(0≤z<E).I_1(z)=z-\min\{R(z),r+1,1+R(E-z)\}\quad(0\le z<E).

Their saturated endpoints are I0(z)=EI_0(z)=E for z≥Mz\ge M and I1(z)=MI_1(z)=M for z≥Ez\ge E. Let τ\tau be the first saturated solo layer and L=τ−1L=\tau-1. Every odd rectangle already has the exact one-day interval 2τ−1≤T≤2τ2\tau-1\le T\le2\tau, an exact joint evaluator, and sufficient solo central test. The new all-length result makes that test necessary for feasible budgets k>=r+1 satisfying

k≤2ror27k3≤r4.k\le2r\quad\text{or}\quad27k^3\le r^4.

In these ranges,

T=2τ−1{E+M−D0(L)−D1(L)≤k}.T=2\tau-\mathbf1_{\{E+M-D_0(L)-D_1(L)\le k\}}.

The inspections are directly specified by the canonical solo prefixes, reflection and the central intersection, or the ordinary two-half solo construction. There is no optimizing joint path left in these ranges. The recurrence still needs bounded numerical evaluation when the fixed block hypothesis fails. Proof: research/bridge-odd-clock-linear-budget-all.md and research/bridge-odd-clock-superlinear-budget.md.

A smaller explicit onset

In the remaining intermediate range r+2≤k≤r2r+2\le k\le r^2, put

G=k−1,H=r2+1,K0=r2+2k(⌊G/(2r+1)⌋+1),G=k-1,\quad H=r^2+1,\quad K_0=r^2+2k(\lfloor G/(2r+1)\rfloor+1), q=max⁡{⌈r⌉,⌈G/(r−1)⌉},u=⌈q(r+1)+G2q⌉,K=min⁡{K0,(q−1)k+u(u−1)},q=\max\{\lceil\sqrt r\rceil,\lceil G/(r-1)\rceil\},\quad u=\left\lceil\frac{q(r+1)+G}{2q}\right\rceil,\quad K=\min\{K_0,(q-1)k+u(u-1)\}, J=max⁡{2K+k+1,K+H},W=2⌈G⌉,Mnew=J+G+k(W+1).J=\max\{2K+k+1,K+H\},\quad W=2\lceil\sqrt G\rceil, \quad M_{\rm new}=J+G+k(W+1).

The scalar test is necessary if M≥MnewM\ge M_{\rm new}. These are fixed-size expressions. The quantity W is used in the proof of the onset; it is not iterated to evaluate the answer. A possible remaining scalar counterexample at fixed width is confined to n=O(r2)n=O(r^2), improving the old O(r4)O(r^4) containing range. No smallest-onset claim is made.

A fixed recent-reset condition

Write Δi=D0(i)−D1(i)\Delta_i=D_0(i)-D_1(i). If ΔL=0\Delta_L=0, the scalar test is exact. Otherwise let p be its slower physical color, and put c=⌈(Cp−k)/2⌉c=\lceil(C_p-k)/2\rceil, with C0=E,C1=MC_0=E,C_1=M. The test is also exact if, for at least one of the fixed ages j=0,1,…,16j=0,1,\ldots,16 with j≤Lj\le L,

Dp(j)<c,L−j=0 or ΔL−jΔL−j−1≥0.D_p(j)<c,\qquad L-j=0\ \text{or}\ \Delta_{L-j}\Delta_{L-j-1}\ge0.

Under the fixed49-block hypothesis, testing this condition uses at most38 fixed-block calls and16 inverse updates. The seventeen age cases are fixed independently of the board. If the condition fails, it makes no necessity claim. Source: research/bridge-odd-clock-reset.md.

The minimum-budget clock remains an evaluation gap

For every odd rectangle at k=r+1k=r+1, the previously established law is

T=2wn−(8r2−4r−4Lr+4).T=2wn-(8r^2-4r-4L_r+4).

The width-only L_r is the first arrival of the bottom simultaneous recurrence at its minority value r(r-1). Its evaluation takes O(r) root-band stages. Matching bounds and direct optimal inspections were already proved at the scope baseline. No new fixed-size formula for L_r has been obtained. Source: thm:odd-minimum-budget.

5. Current even-area bounds, exact regimes, and constructions

The uniform bound stated at the top applies to all feasible inputs. Earlier one-day ranges remain valid: in particular every even-area rectangle with w≥4w\ge4 and k≥⌈4w/3⌉k\ge\lceil4w/3\rceil has the established one-day bracket below its two-day endpoint. For even widths the earlier sufficient threshold is ⌈13w/10⌉\lceil13w/10\rceil. The older exact high-budget, finite-width, and individually certified cases are retained. The current uniform ceiling is two; the preceding public ceiling was four. This does not imply the same improvement for each individual instance.

Exact even-width transport families

Let w=2bw=2b, b≥32b\ge32, and k=b+dk=b+d. The bounds match when

  • d=1d=1, for every n≥2bn\ge2b;
  • 2≤d≤b−12\le d\le b-1, for every n≥2b+2d−2n\ge2b+2d-2.

Put h=bnh=bn, H=b(b−1)H=b(b-1), R(x)=⌈x⌉R(x)=\lceil\sqrt{x}\rceil, and ρ(x)=min⁡{r≥0:x≤r(r+1)}\rho(x)=\min\{r\ge0:x\le r(r+1)\}. Define simultaneous pairs

A0=(0,0),Aj+1=(Aj[1]+k−ρ(Aj[1]+k), Aj[0]+k−R(Aj[0]+k)),A_0=(0,0),\quad A_{j+1}=(A_j[1]+k-\rho(A_j[1]+k),\ A_j[0]+k-R(A_j[0]+k)), V0c=(c,c),Vj+1c=(k+Vjc[1]−ρ(Vjc[1]), k+Vjc[0]−R(Vjc[0])).V^c_0=(c,c),\quad V^c_{j+1}=(k+V^c_j[1]-\rho(V^c_j[1]),\ k+V^c_j[0]-R(V^c_j[0])).

Let e(Q)e(Q) and ℓc(Y)\ell_c(Y) be the first times their respective maxima reach QQ and YY. Over all integer endpoints H−d+1≤Q≤HH-d+1\le Q\le H and H+1≤Y≤H+d+1H+1\le Y\le H+d+1, set

J(c)=min⁡Q,Y(e(Q)+⌈h−Q−Yd⌉+ℓc(Y)).J(c)=\min_{Q,Y}\left(e(Q)+\left\lceil\frac{h-Q-Y}{d}\right\rceil+\ell_c(Y)\right).

Then

Tk(2b,n)=J(k)+J(⌊k/2⌋)+1.T_k(2b,n)=J(k)+J(\lfloor k/2\rfloor)+1.

This is an exact finite recurrence and endpoint minimum. The proof gives physical reflection transport and the final concatenation or palindrome; selecting endpoints that attain the stated minimum selects an optimal inspection sequence. This is constructive, but the endpoint optimization has not become a fixed-size numerical expression or an optimization-free parameter rule. Source: upper-exact-even-transport-families.md; independently accepted in lower-exact-even-transport-review.json, both in the October checkpoint directory.

Exact odd-width, even-length natural range

Let w=2b+1w=2b+1, n=2ℓ≥wn=2\ell\ge w, k=b+dk=b+d, and h=(2b+1)ℓh=(2b+1)\ell. If

d≥1,b≥4d+8,(2b+1)(ℓ−b)>2d2,d\ge1,\qquad b\ge4d+8,\qquad(2b+1)(\ell-b)>2d^2,

then every full-origin signed terminal-quota gate has its exact physical prefix clock P(c)P(c), and

Tk(w,n)=P(k)+P(⌊k/2⌋)+1.T_k(w,n)=P(k)+P(\lfloor k/2\rfloor)+1.

For precision, P(c)P(c) is the first time the maximum reaches hh in the following simultaneous recurrence, with hh absorbing:

X0c=(c,c),X^c_0=(c,c), Xt+1c[0]=min⁡{h,k+Xtc[1]−min⁡(ρ(Xtc[1]),R(h−Xtc[1]),b)},X^c_{t+1}[0]=\min\{h,k+X^c_t[1]-\min(\rho(X^c_t[1]),R(h-X^c_t[1]),b)\}, Xt+1c[1]=min⁡{h,k+Xtc[0]−min⁡(R(Xtc[0]),1+ρ(h−Xtc[0]),b+1)}.X^c_{t+1}[1]=\min\{h,k+X^c_t[0]-\min(R(X^c_t[0]),1+\rho(h-X^c_t[0]),b+1)\}.

The concatenation/palindrome rule specifies attaining inspections on the actual board. The proof constrains one actual hypothetical faster history at one common time, keeping both phases and their combined unused allowance. It does not assume that arbitrary partial states are optimized by prefixes. The length condition holds for every admissible length whenever also b≥d2b\ge d^2. At d=1d=1 this includes every odd width w≥25w\ge25 and every even n≥wn\ge w. Sources: lower-full-front-exact-gates.md, its independent upper and root reviews, and the separate reviewed minimum-budget argument.

Stronger exact criterion from the actual central span

Under the same guard b≥4d+8b\ge4d+8, define the genuine capped forward pair

C0=(0,0),C_0=(0,0), Ct+1=(max⁡{Ct[1]+k−ρ(Ct[1]+k),Ct[1]+d},max⁡{Ct[0]+k−R(Ct[0]+k),Ct[0]+d−1}).C_{t+1}=(\max\{C_t[1]+k-\rho(C_t[1]+k),C_t[1]+d\}, \max\{C_t[0]+k-R(C_t[0]+k),C_t[0]+d-1\}).

At its first time ss with min⁡Cs>b2\min C_s>b^2, set D=Cs[0]−Cs[1]D=C_s[0]-C_s[1] and G=max⁡{∣D∣,∣1−D∣}G=\max\{|D|,|1-D|\}. We have 1≤G≤d1\le G\le d. Put A=h−b2−kA=h-b^2-k. The same exact formula and attaining inspections hold if

A−b2>2G(d−1)+d.A-b^2>2G(d-1)+d.

This subsumes the preceding length condition. In particular, G≤3G\le3 suffices for every admissible length under the natural guard. The actual orbit must be evaluated: there is no claim that G≤3G\le3 always holds. Source: upper-central-span-exact-gates.md, independently accepted in lower-central-span-exact-gates-review.json.

Later verification and geometric tools

The previous 24 October proof tools have since been strengthened: the critical even-width collar classification now includes squares with their appropriate orientation alternatives; the normalized overlap estimates were assembled with actual finite-board hypotheses in their stated large-width ranges. The new current theorem does not imply that arbitrary endpoint shapes are reachable at scalar clocks. See the current checkpoint and gaps assessment.

The former 751-profile symbolic comparison, at odd width 2b+12b+1, b≥32b\ge32, 2≤k−b≤b−32\le k-b\le b-3 and even length, was independently accepted in the later 24 October continuation. The independent replay discharged 4,507 universal obligations, and a separate physical interface supplied entrance, marker, range and stopping hypotheses. It is not a complete Lean theorem or an exact reachability automaton. The earlier candidate zip is a preserved discovery snapshot, not its current acceptance status.

6. Verification and scope boundary

Complete physical-game Lean classifications in the main scope remain paths and two-row boards. The 29 October release adds PairedCompression, an abstract theorem about complement-dual compression, actual prefix histories and joining overlap under explicit hypotheses. The canonical source tree now has 84 modules; this new tool does not formalize the global two-day bound or the new exact wide-rectangle statements. Those retain ordinary proofs, internal independent reviews and exact certificates where stated. The scope manifests preserve one authoritative source tree and the parked companion’s separate coverage.

The exact even-area boundary representation and exact odd joint evaluator remain valuable achievements. Their parameter-dependent optimization does not meet the fixed-size numerical goal or the direct optimal inspection requirement throughout the remaining ranges. Independent higher-dimensional, varying-budget and unrelated partial-state objectives remain parked. RECTANGLE_GAPS.md records the remaining proof tasks; BOX_RECONCILIATION.md distinguishes baseline coverage, new mathematics, and the still-open numerical obligations.